This one is very boring. Bet that when a number shows twice in a row it will come up the third time in a row. Just bet it one time and take it off. Do not go for a fourth time. Do not play on the come-out roll... this seems obvious... but, I mean that if it comes out let's say 6,6 (you made the point right away) you do not bet the 6 on the next come-out roll.
In my trials it seems to work much better for the 6/8... the 10 is terrible and seems to lose much more than it wins... it won 5 times and lost 16 times... since it pays 9:5 (or pay a 5% vig) that is very poor performance. On the other hand, the 6/8 had (combined) 82 wins and only 68 losses... this is great, considering that each win pays 7:6. You would probably have to hold your spot at the table by playing something like pass or don't pass. My thought is a bet that the decision before the last one will repeat, and use the table minimum. Then, make your large bet when the time is right. Maybe the dealers will think that you are just playing a hunch! You might want to take a look at my "12 method." That is another method that you could just add into this one.